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GCSE / IGCSE Chemistry – Chemical Changes and Energy

Reactivity series, acids and bases, electrolysis, energy changes.

12 questions  ·  37 marks  ·  answers included  ·  GCSE / IGCSE (Edexcel / Cambridge style)
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This worksheet covers:

  • This worksheet covers the reactivity series
  • Acids and bases
  • Electrolysis
  • Energy changes

Use the relative atomic masses given in each question (rounded to whole numbers, as used at GCSE/IGCSE level); a calculator is allowed.

Questions

Section A – Reactivity and Acids/Bases

Skills
1

Place the following metals in order of reactivity, most reactive first: copper, magnesium, zinc, iron.

Show answer
Magnesium, zinc, iron, copper (most to least reactive).
[2]
2

Write the balanced symbol equation, including state symbols, for the reaction between magnesium and dilute hydrochloric acid.

Show answer
$\text{Mg}(s) + 2\text{HCl}(aq) \rightarrow \text{MgCl}_2(aq) + \text{H}_2(g)$
[3]
3

Define “neutralisation” and write the balanced symbol equation for the reaction between sodium hydroxide and sulfuric acid.

Show answer
Neutralisation is the reaction between an acid and a base in which they react to form a salt and water. $2\text{NaOH}(aq) + \text{H}_2\text{SO}_4(aq) \rightarrow \text{Na}_2\text{SO}_4(aq) + 2\text{H}_2\text{O}(l)$
[3]
4

Calculate the relative formula mass ($M_r$) of calcium carbonate, $\text{CaCO}_3$. ($A_r$: Ca $=40$, C $=12$, O $=16$)

Show answer
$M_r = 40 + 12 + (3\times16) = 40+12+48 = 100$.
[2]

Section B – Electrolysis and Energy Changes

Exam-style
5

Explain, using ionic half-equations, what happens at each electrode during the electrolysis of molten lead(II) bromide, $\text{PbBr}_2$.

Show answer
At the cathode (negative electrode), $\text{Pb}^{2+}$ ions are reduced (gain electrons) to form lead metal: $\text{Pb}^{2+} + 2e^{-} \rightarrow \text{Pb}$. At the anode (positive electrode), $\text{Br}^{-}$ ions are oxidised (lose electrons) to form bromine: $2\text{Br}^{-} \rightarrow \text{Br}_2 + 2e^{-}$.
[4]
6

Explain why aluminium is extracted by electrolysis rather than by reduction with carbon.

Show answer
Aluminium is more reactive than carbon, so carbon cannot remove the oxygen from (reduce) aluminium oxide. Electrolysis of molten aluminium oxide (dissolved in molten cryolite to lower its melting point) is used instead to separate the aluminium and oxygen.
[2]
7

In an experiment, $50\,\text{cm}^3$ of dilute hydrochloric acid at $20.0^{\circ}\text{C}$ was reacted with excess magnesium ribbon. The maximum temperature reached was $34.5^{\circ}\text{C}$. Calculate the temperature change, and state whether the reaction is exothermic or endothermic.

Show answer
$\Delta T = 34.5-20.0 = 14.5^{\circ}\text{C}$ (a rise). The reaction is exothermic, since the temperature increases as energy is released to the surroundings.
[2]
8

Using the temperature change in the previous question, calculate the energy change in joules, given the specific heat capacity of the solution is $4.2\,\text{J/g}^{\circ}\text{C}$ and the mass of solution is $50\,\text{g}$.

Show answer
$Q=mc\Delta T = 50\times4.2\times14.5 = 3045\,\text{J}$ (3.045 kJ).
[3]

Section C – Extended / Challenge

9

A student carries out an electrolysis experiment using a copper sulfate solution to electroplate a metal spoon with copper.(a) State which electrode, anode or cathode, the spoon should be, and explain why.(b) Write the half-equation for the reaction occurring at the copper anode used in electroplating.

Show answer
(a) The spoon should be the cathode (negative electrode), so that positively charged $\text{Cu}^{2+}$ ions in the solution are attracted to it and are reduced (gain electrons) to deposit as a layer of copper metal on its surface.(b) At the copper anode: $\text{Cu}(s) \rightarrow \text{Cu}^{2+}(aq) + 2e^{-}$ (the copper anode dissolves, releasing copper ions into solution).
[4]
10

Using bond energies, calculate the overall enthalpy change for the reaction $\text{H}_2 + \text{Cl}_2 \rightarrow 2\text{HCl}$, given: bond energy H–H $=+436\,\text{kJ/mol}$, Cl–Cl $=+243\,\text{kJ/mol}$, H–Cl $=+432\,\text{kJ/mol}$.

Show answer
Energy to break bonds $=436+243=679\,\text{kJ/mol}$. Energy released forming bonds $=2\times432=864\,\text{kJ/mol}$. $\Delta H = 679-864=-185\,\text{kJ/mol}$ (exothermic).
[4]
11

Calculate the percentage of aluminium by mass in aluminium oxide, $\text{Al}_2\text{O}_3$. ($A_r$: Al $=27$, O $=16$)

Show answer
$M_r(\text{Al}_2\text{O}_3)=(2\times27)+(3\times16)=54+48=102$. Percentage Al $=\dfrac{54}{102}\times100=52.9\%$ (3 s.f.).
[3]
12

A displacement reaction occurs when zinc granules are added to copper(II) sulfate solution.(a) Write the balanced symbol equation for this reaction.(b) Explain, in terms of electron transfer, why this is a redox reaction, identifying which species is oxidised and which is reduced.

Show answer
(a) $\text{Zn}(s) + \text{CuSO}_4(aq) \rightarrow \text{ZnSO}_4(aq) + \text{Cu}(s)$(b) Zinc atoms lose electrons to form $\text{Zn}^{2+}$ ions (oxidation), while $\text{Cu}^{2+}$ ions gain electrons to form copper atoms (reduction). Since oxidation and reduction both occur, this is a redox reaction.
[5]

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