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GCSE / IGCSE Maths – Algebra

Expanding, factorising, equations, inequalities, sequences, functions.

12 questions  ·  60 marks  ·  answers included  ·  GCSE/IGCSE (Higher)
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This worksheet covers:

  • Higher-tier practice covering expanding and factorising
  • Linear and quadratic equations
  • Inequalities
  • Simultaneous equations
  • Sequences
  • Functions
  • Rearranging formulae

Section A is non-calculator; a calculator may be used for Sections B and C. Allow about 60 minutes.

Questions

Section A – Skills

Non-calculator.
1

(a) Expand and simplify $(2x – 3)(x + 5)$.(b) Expand $(x + 4)^2$.(c) Factorise fully $9x^2 – 16$.(d) Factorise $3x^2 + 7x – 6$.

Show answer
(a) $2x^2 + 7x – 15$(b) $x^2 + 8x + 16$(c) $(3x – 4)(3x + 4)$(d) $(3x – 2)(x + 3)$
[7]
2

Solve(a) $3(2x – 1) = 4x + 7$(b) $\dfrac{x + 2}{3} – \dfrac{x – 1}{4} = 2$

Show answer
(a) $6x – 3 = 4x + 7$, $x = 5$(b) $4(x+2) – 3(x-1) = 24 \Rightarrow x + 11 = 24$, $x = 13$
[5]
3

Here are the first four terms of a sequence: $5,\ 9,\ 13,\ 17$.(a) Write down an expression for the $n$th term.(b) Is 203 a term of the sequence? Justify your answer.(c) The first three terms of a geometric sequence are $3,\ 6,\ 12$. Write down the $n$th term.

Show answer
(a) $4n + 1$(b) $4n + 1 = 203 \Rightarrow n = 50.5$, not a whole number, so no.(c) $3 \times 2^{n-1}$
[5]
4

Solve the simultaneous equations$3x + 2y = 12$$5x – 2y = 4$

Show answer
Adding: $8x = 16$, $x = 2$, $y = 3$
[3]
5

(a) Solve the inequality $5x – 3 > 2x + 9$.(b) Write down the integer values of $x$ that satisfy $-4 < 2x \leq 6$.

Show answer
(a) $3x > 12$, $x > 4$(b) $-2 < x \leq 3$: $-1, 0, 1, 2, 3$
[4]

Section B – Exam-style

Calculator allowed.
6

(a) Solve $2x^2 – 5x – 3 = 0$ by factorising.(b) Solve $2x^2 – 3x – 7 = 0$, giving your answers correct to 3 significant figures.

Show answer
(a) $(2x + 1)(x – 3) = 0$, $x = -\tfrac{1}{2}$ or $x = 3$(b) $x = \dfrac{3 \pm \sqrt{65}}{4}$, $x = 2.77$ or $x = -1.27$
[6]
7

The functions $f$ and $g$ are defined by $f(x) = 3x – 2$ and $g(x) = x^2 + 1$.(a) Find $fg(2)$.(b) Find an expression for $gf(x)$, simplifying your answer.(c) Find $f^{-1}(x)$.

Show answer
(a) $g(2) = 5$, $f(5) = 13$(b) $(3x-2)^2 + 1 = 9x^2 – 12x + 5$(c) $f^{-1}(x) = \dfrac{x + 2}{3}$
[6]
8

Make $x$ the subject of $y = \dfrac{2x + 3}{x – 1}$.

Show answer
$y(x – 1) = 2x + 3 \Rightarrow xy – 2x = y + 3 \Rightarrow x = \dfrac{y + 3}{y – 2}$
[4]
9

The $n$th term of a quadratic sequence is given by the first four terms $2,\ 7,\ 16,\ 29$. Find an expression for the $n$th term.

Show answer
First differences $5, 9, 13$; second difference $4$, so $2n^2$ term. Subtracting $2n^2$ leaves $0, -1, -2, -3 = 1 – n$. $n$th term $= 2n^2 – n + 1$
[4]
10

(a) Write $2x^2 + 12x + 5$ in the form $a(x + b)^2 + c$.(b) Hence write down the coordinates of the turning point of the graph of $y = 2x^2 + 12x + 5$.

Show answer
(a) $2(x + 3)^2 – 13$(b) $(-3, -13)$
[4]

Section C – Problem solving

Calculator allowed.
11

Solve the simultaneous equations$x^2 + y^2 = 25$$y = x + 1$

Show answer
$x^2 + (x+1)^2 = 25 \Rightarrow 2x^2 + 2x – 24 = 0 \Rightarrow (x + 4)(x – 3) = 0$.$x = 3, y = 4$ or $x = -4, y = -3$
[5]
12

(a) Show that the equation $x^3 – 5x – 2 = 0$ has a solution between $x = 2$ and $x = 3$.(b) Show that the equation can be rearranged to $x = \sqrt[3]{5x + 2}$.(c) Starting with $x_0 = 2$, use the iteration $x_{n+1} = \sqrt[3]{5x_n + 2}$ to find $x_1$, $x_2$ and $x_3$ to 4 decimal places.(d) Solve the inequality $x^2 – 2x – 15 < 0$.

Show answer
(a) $f(2) = -4 < 0$, $f(3) = 12 > 0$; sign change so a root lies between 2 and 3.(b) $x^3 = 5x + 2 \Rightarrow x = \sqrt[3]{5x + 2}$(c) $x_1 = 2.2894$, $x_2 = 2.3780$, $x_3 = 2.4038$(d) $(x – 5)(x + 3) < 0$, so $-3 < x < 5$
[7]

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