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AP Calculus AB – Practice Set

Limits, derivatives, applications, integrals, differential equations. MCQ and FRQ style.

12 questions  ·  71 marks  ·  answers included  ·  AP Calculus AB
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This worksheet covers:

  • Limits and continuity
  • Derivatives and their applications
  • Integrals and the Fundamental Theorem
  • Separable differential equations

Section A is short-answer in the style of multiple-choice items (no calculator); Sections B and C are free-response style. Allow about 90 minutes.

Questions

Section A – Short answer (MCQ style)

No calculator
1

Evaluate each limit.(a) $\displaystyle\lim_{x \to 3} \frac{x^2 – 9}{x – 3}$(b) $\displaystyle\lim_{x \to \infty} \frac{3x^2 + 1}{2x^2 – x}$(c) $\displaystyle\lim_{x \to 0} \frac{\sin 5x}{x}$(d) $\displaystyle\lim_{x \to 0^+} \frac{\ln x}{x}$

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(a) $6$(b) $\dfrac{3}{2}$(c) $5$(d) $-\infty$
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2

Find $\dfrac{dy}{dx}$ for each function.(a) $y = x^2 e^{3x}$(b) $y = \ln(\cos x)$(c) $y = \dfrac{x}{x^2 + 1}$(d) $y = \arctan(2x)$

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(a) $e^{3x}(2x + 3x^2)$(b) $-\tan x$(c) $\dfrac{1 – x^2}{(x^2 + 1)^2}$(d) $\dfrac{2}{1 + 4x^2}$
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3

The curve $x^2 + y^2 = 25$ passes through the point $(3, 4)$.(a) Use implicit differentiation to find $\dfrac{dy}{dx}$ in terms of $x$ and $y$.(b) Write an equation of the line tangent to the curve at $(3, 4)$.

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(a) $\dfrac{dy}{dx} = -\dfrac{x}{y}$(b) $y – 4 = -\dfrac{3}{4}(x – 3)$
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4

Evaluate each integral.(a) $\displaystyle\int (3x^2 – 4x + 1)\,dx$(b) $\displaystyle\int_0^{\pi/2} \cos x\,dx$(c) $\displaystyle\int \frac{x}{x^2 + 1}\,dx$(d) $\displaystyle\int_1^{e} \frac{\ln x}{x}\,dx$

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(a) $x^3 – 2x^2 + x + C$(b) $1$(c) $\dfrac{1}{2}\ln(x^2 + 1) + C$(d) $\dfrac{1}{2}$
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5

Let $g(x) = \displaystyle\int_1^{x^2} \sin t\,dt$.(a) Find $g'(x)$.(b) Find $g’\left(\sqrt{\pi/2}\right)$.

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(a) $g'(x) = 2x\sin(x^2)$(b) $2\sqrt{\pi/2}\cdot\sin(\pi/2) = \sqrt{2\pi}$
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6

Let $f(x) = \dfrac{x^2 – 4}{x – 2}$ for $x e 2$ and $f(2) = k$.(a) Find the value of $k$ that makes $f$ continuous at $x = 2$.(b) With this value of $k$, is $f$ differentiable at $x = 2$? Justify your answer.(c) The function $h(x) = \dfrac{1}{x – 2}$ has a discontinuity at $x = 2$. State the type of discontinuity.

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(a) $k = 4$(b) Yes: with $k = 4$, $f(x) = x + 2$ for all $x$, so $f'(2) = 1$(c) Infinite (non-removable) discontinuity; $x = 2$ is a vertical asymptote
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Section B – Free response

Calculator allowed
7

A particle moves along the $x$-axis with velocity $v(t) = t^2 – 4t + 3$ for $0 \le t \le 5$, where $t$ is in seconds and $v$ in metres per second. At $t = 0$ the particle is at $x = 2$.(a) Find all times at which the particle is at rest.(b) Find the displacement of the particle over $0 \le t \le 5$.(c) Find the total distance travelled over $0 \le t \le 5$.(d) Find the position of the particle at $t = 5$.(e) Is the speed of the particle increasing or decreasing at $t = 2$? Justify your answer.

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(a) $t = 1$ and $t = 3$(b) $\displaystyle\int_0^5 v(t)\,dt = \dfrac{20}{3}\,\text{m}$(c) $\dfrac{4}{3} + \dfrac{4}{3} + \dfrac{20}{3} = \dfrac{28}{3} \approx 9.33\,\text{m}$(d) $x(5) = 2 + \dfrac{20}{3} = \dfrac{26}{3}$(e) $v(2) = -1 < 0$, $a(2) = 2(2) – 4 = 0$; since $a(2) = 0$ the speed is neither increasing nor decreasing at that instant
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8

A $10$-foot ladder leans against a vertical wall. The bottom of the ladder slides away from the wall at a constant rate of $2$ feet per second.(a) Find the rate at which the top of the ladder is sliding down the wall when the bottom is $6$ feet from the wall.(b) Find the rate of change of the area of the triangle formed by the ladder, the wall and the ground at that instant.

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(a) $x^2 + y^2 = 100 \Rightarrow \dfrac{dy}{dt} = -\dfrac{x}{y}\dfrac{dx}{dt} = -\dfrac{6}{8}(2) = -1.5\,\text{ft/s}$ (moving down at $1.5$ ft/s)(b) $A = \dfrac{1}{2}xy$, $\dfrac{dA}{dt} = \dfrac{1}{2}\left(y\dfrac{dx}{dt} + x\dfrac{dy}{dt}\right) = \dfrac{1}{2}(16 – 9) = 3.5\,\text{ft}^2\text{/s}$
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9

An open-top box with a square base is to have a volume of $32$ cubic feet. Let $x$ be the side length of the base and $h$ the height.(a) Express the surface area $S$ of the box (base plus four sides) as a function of $x$ alone.(b) Find the dimensions that minimize the surface area, and justify that your answer gives a minimum.(c) State the minimum surface area.

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(a) $h = \dfrac{32}{x^2}$, $S(x) = x^2 + \dfrac{128}{x}$, $x > 0$(b) $S'(x) = 2x – \dfrac{128}{x^2} = 0 \Rightarrow x^3 = 64$, $x = 4$, $h = 2$; $S”(x) = 2 + \dfrac{256}{x^3} > 0$ so minimum(c) $S(4) = 16 + 32 = 48\,\text{ft}^2$
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10

Consider the differential equation $\dfrac{dy}{dx} = xy$ with $y(1) = 2$.(a) Write an equation of the line tangent to the solution curve at $(1, 2)$ and use it to approximate $y(1.2)$.(b) Find the particular solution $y = f(x)$.(c) Use your solution to find $y(1.2)$ to three decimal places, and state whether the tangent-line approximation is an over- or under-estimate. Justify using $\dfrac{d^2y}{dx^2}$.

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(a) Slope $= 2$: $y = 2 + 2(x – 1)$; $y(1.2) \approx 2.4$(b) $\ln y = \dfrac{x^2}{2} + C$, $C = \ln 2 – \dfrac{1}{2}$; $y = 2e^{(x^2 – 1)/2}$(c) $y(1.2) = 2e^{0.22} = 2.492$; underestimate because $\dfrac{d^2y}{dx^2} = y + x\dfrac{dy}{dx} = y + x^2 y > 0$ (concave up near $x = 1$)
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Section C – Extended free response

Calculator allowed
11

Let $R$ be the region in the first quadrant bounded by $y = \sqrt{x}$ and $y = \dfrac{x}{2}$.(a) Find the $x$-coordinates of the points of intersection.(b) Find the area of $R$.(c) Find the volume of the solid generated when $R$ is rotated about the $x$-axis.(d) The region $R$ is the base of a solid whose cross-sections perpendicular to the $x$-axis are squares. Find the volume of this solid.

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(a) $\sqrt{x} = \dfrac{x}{2} \Rightarrow x = 0,\ 4$(b) $\displaystyle\int_0^4 \left(\sqrt{x} – \dfrac{x}{2}\right)dx = \dfrac{16}{3} – 4 = \dfrac{4}{3}$(c) $\pi\displaystyle\int_0^4 \left(x – \dfrac{x^2}{4}\right)dx = \pi\left(8 – \dfrac{16}{3}\right) = \dfrac{8\pi}{3}$(d) $\displaystyle\int_0^4 \left(\sqrt{x} – \dfrac{x}{2}\right)^2 dx = 8 – \dfrac{64}{5} + \dfrac{16}{3} = \dfrac{8}{15}$
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12

Let $f(x) = x^3 – 6x^2 + 9x + 1$.(a) Find the intervals on which $f$ is increasing and decreasing.(b) Find the $x$-coordinates of all relative extrema and classify each.(c) Find the point of inflection of the graph of $f$.(d) Find the absolute maximum and absolute minimum values of $f$ on $[0, 4]$.(e) Verify that the Mean Value Theorem applies to $f$ on $[0, 4]$ and find all values of $c$ guaranteed by the theorem.

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(a) $f'(x) = 3(x – 1)(x – 3)$: increasing on $(-\infty, 1)$ and $(3, \infty)$, decreasing on $(1, 3)$(b) Relative maximum at $x = 1$ ($f = 5$), relative minimum at $x = 3$ ($f = 1$)(c) $f”(x) = 6x – 12 = 0 \Rightarrow (2, 3)$(d) $f(0) = 1$, $f(1) = 5$, $f(3) = 1$, $f(4) = 5$: absolute max $5$, absolute min $1$(e) $f$ is a polynomial (continuous and differentiable); $\dfrac{f(4) – f(0)}{4} = 1$; $3c^2 – 12c + 9 = 1 \Rightarrow c = 2 \pm \dfrac{2\sqrt{3}}{3}$, i.e. $c \approx 0.845,\ 3.155$
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