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IB Maths AI HL – Topic 1: Number and Algebra

Complex numbers, matrices, eigenvalues, transformations.

12 questions  ·  70 marks  ·  answers included  ·  IB AI HL
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This worksheet covers:

  • Complex numbers in Cartesian
  • Polar and Euler form
  • Matrix algebra
  • Eigenvalues and eigenvectors
  • Matrix transformations

A GDC is allowed throughout; allow about 70 minutes.

Questions

Section A – Core skills

Give exact answers unless otherwise stated.
1

Let $z_1 = 3 + 4i$ and $z_2 = 1 – 2i$.(a) Find $z_1 z_2$ in the form $a + bi$.(b) Find $\dfrac{z_1}{z_2}$ in the form $a + bi$.(c) Find $|z_1|$.

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(a) $11 – 2i$(b) $-1 + 2i$(c) $5$
[5]
2

Let $z = -1 + \sqrt{3}\,i$.(a) Write $z$ in the form $r\,\text{cis}\,\theta$ with $-\pi < \theta \le \pi$.(b) Write $z$ in Euler form $re^{i\theta}$.(c) Hence find $z^6$.

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(a) $2\,\text{cis}\left(\frac{2\pi}{3}\right)$(b) $2e^{2\pi i/3}$(c) $z^6 = 64e^{4\pi i} = 64$
[5]
3

Solve $z^3 = 8i$, giving the roots in the form $a + bi$ with exact values.

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$8i = 8\,\text{cis}\frac{\pi}{2}$; roots $2\,\text{cis}\frac{\pi}{6}, 2\,\text{cis}\frac{5\pi}{6}, 2\,\text{cis}\frac{3\pi}{2}$, i.e. $z = \sqrt{3} + i,\; -\sqrt{3} + i,\; -2i$
[5]
4

Let $\mathbf{A} = \begin{pmatrix} 2 & 1 \\ 3 & 4 \end{pmatrix}$ and $\mathbf{B} = \begin{pmatrix} 1 & 0 \\ -2 & 5 \end{pmatrix}$.(a) Find $\mathbf{AB}$.(b) Find $\det \mathbf{A}$.(c) Find $\mathbf{A}^{-1}$.

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(a) $\begin{pmatrix} 0 & 5 \\ -5 & 20 \end{pmatrix}$(b) $5$(c) $\frac{1}{5}\begin{pmatrix} 4 & -1 \\ -3 & 2 \end{pmatrix}$
[5]
5

Use the inverse matrix from question 4 to solve the simultaneous equations $2x + y = 7$ and $3x + 4y = 18$. Show the matrix method clearly.

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$\begin{pmatrix} x \\ y \end{pmatrix} = \frac{1}{5}\begin{pmatrix} 4 & -1 \\ -3 & 2 \end{pmatrix}\begin{pmatrix} 7 \\ 18 \end{pmatrix} = \begin{pmatrix} 2 \\ 3 \end{pmatrix}$, so $x = 2,\; y = 3$
[3]

Section B – Exam-style

6

Let $\mathbf{M} = \begin{pmatrix} 4 & 1 \\ 2 & 3 \end{pmatrix}$.(a) Show that the characteristic equation of $\mathbf{M}$ is $\lambda^2 – 7\lambda + 10 = 0$.(b) Find the eigenvalues of $\mathbf{M}$.(c) Find a corresponding eigenvector for each eigenvalue.

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(a) $\det(\mathbf{M} – \lambda\mathbf{I}) = (4-\lambda)(3-\lambda) – 2 = \lambda^2 – 7\lambda + 10$(b) $\lambda = 5,\; \lambda = 2$(c) $\lambda = 5$: $\begin{pmatrix} 1 \\ 1 \end{pmatrix}$; $\lambda = 2$: $\begin{pmatrix} 1 \\ -2 \end{pmatrix}$ (any non-zero multiples)
[7]
7

A triangle has vertices $P(1, 1)$, $Q(3, 1)$ and $R(1, 4)$. It is rotated $90^\circ$ anticlockwise about the origin and the image is then reflected in the line $y = x$.(a) Write down the matrix for each transformation.(b) Find the single matrix representing the combined transformation, and describe it geometrically.(c) Find the coordinates of the image of the triangle.

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(a) Rotation $\begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix}$, reflection $\begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}$(b) $\begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}\begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix} = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}$: a reflection in the $x$-axis(c) $P'(1, -1),\; Q'(3, -1),\; R'(1, -4)$
[7]
8

The transformation $\mathbf{T} = \begin{pmatrix} 3 & 1 \\ 1 & 2 \end{pmatrix}$ is applied to a square of area $4$ square units.(a) Find $\det \mathbf{T}$.(b) State the area of the image.(c) The image is a parallelogram. Explain why it cannot be a rectangle by considering the images of the unit vectors $\mathbf{i}$ and $\mathbf{j}$.

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(a) $5$(b) $20$ square units(c) Images are $\begin{pmatrix} 3 \\ 1 \end{pmatrix}$ and $\begin{pmatrix} 1 \\ 2 \end{pmatrix}$; their scalar product is $3 + 2 = 5 e 0$, so the image sides are not perpendicular
[5]
9

Using the eigenvalues and eigenvectors of $\mathbf{M} = \begin{pmatrix} 4 & 1 \\ 2 & 3 \end{pmatrix}$ from question 6:(a) Write $\mathbf{M}$ in the form $\mathbf{PDP}^{-1}$, stating $\mathbf{P}$, $\mathbf{D}$ and $\mathbf{P}^{-1}$.(b) Hence find an expression for $\mathbf{M}^n$.(c) Find $\mathbf{M}^5$.

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(a) $\mathbf{P} = \begin{pmatrix} 1 & 1 \\ 1 & -2 \end{pmatrix}$, $\mathbf{D} = \begin{pmatrix} 5 & 0 \\ 0 & 2 \end{pmatrix}$, $\mathbf{P}^{-1} = \frac{1}{3}\begin{pmatrix} 2 & 1 \\ 1 & -1 \end{pmatrix}$(b) $\mathbf{M}^n = \frac{1}{3}\begin{pmatrix} 2 \cdot 5^n + 2^n & 5^n – 2^n \\ 2 \cdot 5^n – 2^{n+1} & 5^n + 2^{n+1} \end{pmatrix}$(c) $\mathbf{M}^5 = \begin{pmatrix} 2094 & 1031 \\ 2062 & 1063 \end{pmatrix}$
[8]

Section C – Extended

10

Each year $20$ percent of the residents of town A move to town B, and $30$ percent of the residents of town B move to town A. Initially town A has $1000$ residents and town B has $0$. Let $\mathbf{x}_n = \begin{pmatrix} a_n \\ b_n \end{pmatrix}$ be the populations after $n$ years.(a) Write down the transition matrix $\mathbf{T}$ such that $\mathbf{x}_{n+1} = \mathbf{T}\mathbf{x}_n$.(b) Find the populations after $1$ year and after $2$ years.(c) Find the eigenvalues of $\mathbf{T}$.(d) Hence find the long-term populations of the two towns.

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(a) $\mathbf{T} = \begin{pmatrix} 0.8 & 0.3 \\ 0.2 & 0.7 \end{pmatrix}$(b) Year 1: $(800, 200)$; year 2: $(700, 300)$(c) $\lambda = 1$ and $\lambda = 0.5$(d) Steady state is the eigenvector for $\lambda = 1$, with $a : b = 3 : 2$, so $600$ in A and $400$ in B
[8]
11

Two alternating voltages are $v_1 = 5\sin(\omega t)$ and $v_2 = 12\sin\left(\omega t + \frac{\pi}{2}\right)$, represented by the phasors (complex numbers) $5$ and $12i$ respectively.(a) Write down the phasor representing $v_1 + v_2$.(b) Find the modulus and argument of this phasor, giving the argument in radians to 3 significant figures.(c) Hence write $v_1 + v_2$ in the form $R\sin(\omega t + \alpha)$.

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(a) $5 + 12i$(b) Modulus $13$, argument $\arctan\frac{12}{5} = 1.18$ rad ($1.176$)(c) $v_1 + v_2 = 13\sin(\omega t + 1.18)$
[6]
12

A transformation consists of a stretch with scale factor $3$ parallel to the $x$-axis, followed by a rotation of $45^\circ$ anticlockwise about the origin.(a) Find the single $2 \times 2$ matrix representing the combined transformation, giving entries in exact form.(b) Find the exact image of the point $(2, 0)$.(c) A shape of area $A$ is transformed. Find the area of its image in terms of $A$.

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(a) $\frac{1}{\sqrt{2}}\begin{pmatrix} 1 & -1 \\ 1 & 1 \end{pmatrix}\begin{pmatrix} 3 & 0 \\ 0 & 1 \end{pmatrix} = \frac{1}{\sqrt{2}}\begin{pmatrix} 3 & -1 \\ 3 & 1 \end{pmatrix}$(b) $(3\sqrt{2}, 3\sqrt{2})$(c) $\det = 3$, so area $3A$
[6]

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